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ACT Math Averages Complete Study Guide

ACT Math: Averages – Complete Study Guide | The School of Mathematics
ACT Math — Full Lesson

Averages & Statistical Measures

A complete, test-focused breakdown of every Averages concept on the ACT — mean, median, mode, range, weighted averages, missing value problems, combined averages, and average rate of change — with worked examples and strategy notes for every question type.

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The Four Measures at a Glance

The ACT tests four core statistical measures. Know each one cold — the definitions are simple but the ACT disguises them in multi-step problems designed to catch careless errors.

Measure 01
Mean
The sum of all values divided by how many there are. The most tested measure on the ACT.
Sum ÷ Count
Measure 02
Median
The middle value when data is sorted in order. For even counts, average the two middle values.
Middle value (sorted)
Measure 03
Mode
The value that appears most often. A dataset can have one mode, many modes, or no mode.
Most frequent value
Measure 04
Range
The spread of data — the difference between the largest and smallest values.
Max − Min
💡

Quick memory trick: Mean = Math (you calculate it). Median = Middle (you find it by position). Mode = Most (you count frequency). Range = Reach (how far the data stretches).

Arithmetic Mean (Average)

The mean is the standard "average" everyone learns in school. It is the single most important concept in this lesson — most ACT average problems ultimately reduce to the mean formula used cleverly.

SUM
MEAN
COUNT
Cover the value you want to find — the remaining two tell you what to do with them.
Mean = Sum / Count
Sum = Mean × Count
Count = Sum / Mean
// Know all three rearrangements — the ACT uses all of them
The Sum Is Your Best Friend

On every ACT average problem, convert the average back to a sum as early as possible. Most problems become straightforward once you work with sums rather than averages directly.

📐 Worked Example — Basic Mean
Find the mean of: 14, 8, 21, 6, 31
01Sum: 14 + 8 + 21 + 6 + 31 = 80
02Count: 5 values
03Mean = 80 ÷ 5 = 16
Mean = 16

Properties of the Mean

  • The mean is pulled toward outliers (extremely high or low values).
  • If you add a constant k to every value, the mean increases by k.
  • If you multiply every value by k, the mean is multiplied by k.
  • If you add a value equal to the current mean, the mean does not change.
  • The sum of the deviations from the mean always equals zero: Σ(xᵢ − mean) = 0.
📐 Worked Example — Using Sum = Mean × Count
A student's average score on 5 tests is 82. What is the total number of points she has earned?
01Rearrange: Sum = Mean × Count
02Sum = 82 × 5 = 410 points
Total points = 410
⚠️

ACT trap — the "average of averages" error: If Group A has 3 people averaging 70 and Group B has 7 people averaging 90, the combined average is NOT (70+90)÷2 = 80. You must weight by group size. See Section 08 for the correct method.

Median

The median is the middle value of a dataset when arranged in order from least to greatest. It is resistant to outliers — extreme values do not pull the median the way they pull the mean.

Finding the Median — Two Cases

Odd number of values: Median = the single middle value.
Position = (n + 1) / 2

Even number of values: Median = mean of the two middle values.
Average positions n/2 and (n/2 + 1)

Odd Count — Single Middle Value

Dataset: 3, 7, 9, 12, 18, 22, 25   (7 values — odd)

3
7
9
12
18
22
25

Position: (7+1)/2 = 4th value → Median = 12

Even Count — Average the Two Middle Values

Dataset: 5, 11, 14, 18, 23, 30   (6 values — even)

5
11
14
18
23
30

Two middle values (3rd and 4th): Median = (14 + 18)/2 = 16

📐 Worked Example — Unsorted Data
Find the median of: 42, 17, 68, 5, 31, 29, 53, 11
01Sort ascending: 5, 11, 17, 29, 31, 42, 53, 68
02Count = 8 (even) → middle positions are 4th and 5th: 29 and 31
03Median = (29 + 31) / 2 = 30
Median = 30
⚠️

Must sort first! This is the most common median mistake — finding the middle value of unsorted data. On the ACT, data is often presented in a table or stem-and-leaf plot not in order. Always sort before finding the median position.

When to Use Median vs. Mean

SituationBest MeasureWhy
Symmetric, no outliersMeanUses all data; most informative
Skewed data or outliersMedianNot affected by extreme values
Income / home pricesMedianA few millionaires distort the mean
Test scores (no outliers)MeanCaptures overall performance level

Mode

The mode is the value (or values) that appear most frequently in a dataset. It is the least computationally demanding measure — you simply count frequencies.

Unimodal One value appears more than all others.

{3, 5, 5, 7, 8} → Mode = 5
Bimodal / Multimodal Two or more values tie for highest frequency.

{2, 4, 4, 6, 6, 9} → Mode = 4 and 6
No Mode All values appear with equal frequency (or each appears exactly once).

{1, 3, 5, 7} → No mode
Mode from Frequency Tables The mode is the value with the highest frequency listed in the table.

No sorting or calculation required.
📐 Worked Example — Mode from a Dataset
Find the mode of: 8, 3, 8, 5, 3, 8, 2, 5, 3
01Count frequencies: 2→1, 3→3, 5→2, 8→3
02Both 3 and 8 appear 3 times — tied for highest frequency
Mode = 3 and 8 (bimodal)
💡

ACT context: Mode questions are usually straightforward, but the ACT sometimes hides them in frequency tables, histograms, or dot plots. The strategy is the same: find the value with the tallest bar or highest listed frequency.

Range

The range measures the spread of a dataset. It is the simplest measure of variability and requires only two values from the entire dataset.

Range = Maximum value − Minimum value
📐 Worked Example — Range
Find the range of: 47, 12, 83, 29, 64, 7, 51
01Maximum = 83   Minimum = 7
02Range = 83 − 7 = 76
Range = 76

Range vs. Mean/Median

Range tells you how spread out the data is, not where the center is. Two datasets can have the same mean but very different ranges — the ACT sometimes exploits this distinction.

📐 Worked Example — Same Mean, Different Range
Set A: {8, 9, 10, 11, 12}   Set B: {2, 5, 10, 15, 18} — compare their means and ranges.
01Mean A = (8+9+10+11+12)/5 = 50/5 = 10
02Mean B = (2+5+10+15+18)/5 = 50/5 = 10 → same mean!
03Range A = 12 − 8 = 4   Range B = 18 − 2 = 16
Same mean (10), but Set B is far more spread out (Range 16 vs 4)
⚠️

Range limitation: Because range uses only the two extreme values, a single outlier dramatically changes it. The ACT may ask you to identify which measure is most affected when an outlier is added — the answer is usually the mean and range, while the median is most resistant.

Missing Value Problems

Missing value problems are the most common averages question type on the ACT. You are given the average and all but one value, and asked to find the missing one. The key is always the same: work through the sum.

The Strategy — Always Use Sum

Step 1: Find the required total sum: Sum = Mean × Count
Step 2: Find the sum of the known values.
Step 3: Missing value = Required sum − Known sum

📐 Worked Example — One Missing Value
The average of 6 numbers is 15. Five of the numbers are 12, 18, 9, 21, and 14. What is the sixth number?
01Required sum = Mean × Count = 15 × 6 = 90
02Sum of known five: 12 + 18 + 9 + 21 + 14 = 74
03Missing value = 90 − 74 = 16
The sixth number is 16
📐 Worked Example — What Score Is Needed?
Marcus scored 72, 85, 79, and 88 on four tests. What score must he earn on the fifth test to have an average of 82?
01Required sum = 82 × 5 = 410
02Current sum: 72 + 85 + 79 + 88 = 324
03Required score = 410 − 324 = 86
Marcus needs an 86 on the fifth test
📐 Worked Example — Average Changes After Adding a Value
The average of 5 numbers is 20. When a sixth number is added, the average becomes 18. What is the sixth number?
01Sum of original 5: 20 × 5 = 100
02Sum of new 6: 18 × 6 = 108
03Sixth number = 108 − 100 = 8
04Check: 8 < 18 (new mean), so adding it lowered the average ✓ Makes sense.
The sixth number is 8

Missing Median Problems

The ACT also asks for a missing value that will produce a given median. The approach: place the unknown in the sorted list and determine what value would land in the median position.

📐 Worked Example — Missing Value for a Target Median
The five values 3, x, 11, 15, 20 are listed in order (x is between 3 and 11). What value of x makes the median equal to 10?
01With 5 values in order, the median is the 3rd value
02Sorted order given: 3, x, 11, 15, 20 → 3rd value is 11
03For the median to be 10, x must be 10 (so the order becomes 3, 10, 11, 15, 20 → 3rd value = 11 ✗)
04Wait — if x = 10, sorted list: 3, 10, 11, 15, 20 → median = 11. Need median = 10, so x must occupy the 3rd position. That means x ≥ 11, but x is stated to be < 11. Re-read: x can equal 10 only if we need 3rd value = 10. For that, x must be ≥ 10 and ≤ 11, and the 3rd value = x. So x = 10.
x = 10 gives sorted list: 3, 10, 11, 15, 20 → median = 11. If we need median = 10: x = 10, sorted: 3, 10, 10, 15, 20 → median = 10 ✓ (x = 10)
💡

For missing median problems: First establish the sorted order including the unknown, then identify which position is the median position, then set that position equal to the target median and solve. Always verify by re-inserting your answer into the sorted list.

Weighted Averages

A weighted average accounts for the fact that some values count more than others. Each value is multiplied by its weight (its relative importance), then all weighted values are summed and divided by the total weight.

Weighted Mean = Σ(value × weight) / Σ(weights)
// Σ means "sum of all"
📐 Worked Example — Course Grade Calculation
In a class, homework is worth 20%, midterm 30%, and final exam 50% of the grade. A student scores 90 on homework, 74 on the midterm, and 82 on the final. Find the weighted average grade.
ComponentScoreWeightScore × Weight
Homework900.2090 × 0.20 = 18.0
Midterm740.3074 × 0.30 = 22.2
Final Exam820.5082 × 0.50 = 41.0
Total1.0081.2
Weighted Average Grade = 81.2
📐 Worked Example — Weighted Average with Counts
A store sold 40 items at $5 each, 25 items at $8 each, and 15 items at $12 each. What was the average price per item sold?
01Total revenue: 40×$5 + 25×$8 + 15×$12 = 200 + 200 + 180 = $580
02Total items sold: 40 + 25 + 15 = 80
03Average price = $580 ÷ 80 = $7.25
Average price per item = $7.25
⚠️

Weights must sum to 1 (or 100%). If given weights in percentages (20%, 30%, 50%), convert to decimals first. If weights are counts (40, 25, 15 items), the denominator is the total count (80). Either way, the formula is the same: Σ(value × weight) ÷ Σ(weights).

Combined Group Averages

When two or more groups are merged and you want the overall average, you cannot simply average the group averages — you must account for group sizes. This is one of the most frequently tested ACT traps.

Combined Mean = (Sum₁ + Sum₂) / (Count₁ + Count₂)
= (Mean₁ × Count₁ + Mean₂ × Count₂) / (Count₁ + Count₂)
📐 Worked Example — Two Groups Combined
Class A has 20 students with an average score of 75. Class B has 30 students with an average score of 85. What is the combined average for all 50 students?
01Sum for Class A: 75 × 20 = 1,500
02Sum for Class B: 85 × 30 = 2,550
03Total sum: 1,500 + 2,550 = 4,050
04Total count: 20 + 30 = 50
05Combined mean = 4,050 ÷ 50 = 81
Combined average = 81 (not 80!)
Why Not 80?

The "average of averages" (75+85)÷2 = 80 would only be correct if both groups were the same size. Since Class B is larger (30 vs 20), it pulls the combined average toward 85. The correct answer of 81 is closer to Class B's mean — exactly as expected.

📐 Worked Example — Finding an Unknown Group Average
The average of 10 numbers is 40. The average of a subset of 4 of those numbers is 25. What is the average of the remaining 6 numbers?
01Total sum of all 10: 40 × 10 = 400
02Sum of the 4 known: 25 × 4 = 100
03Sum of the remaining 6: 400 − 100 = 300
04Average of remaining 6: 300 ÷ 6 = 50
Average of remaining 6 numbers = 50

Effect of Adding or Removing Values

The ACT frequently asks how the mean, median, mode, or range change when a value is added, removed, or altered. Think through each measure separately using the sum-and-count framework.

Adding a Value

  • If the new value equals the current mean → the mean stays the same; count increases by 1.
  • If the new value is above the mean → the mean increases.
  • If the new value is below the mean → the mean decreases.
  • The median may or may not change — must re-sort to check.
  • The range may increase if the new value is above the max or below the min.
📐 Worked Example — Adding a Value Changes the Mean
Dataset: {10, 14, 18, 22, 26} — mean = 18. A new value of 30 is added. Find the new mean.
01Old sum = 18 × 5 = 90
02New sum = 90 + 30 = 120
03New count = 6
04New mean = 120 ÷ 6 = 20
New mean = 20 (increased from 18 because 30 > 18)

Removing a Value

  • Removing the maximum decreases the range (and may decrease the mean).
  • Removing the minimum increases the minimum, so range decreases (and may increase the mean).
  • Removing a value equal to the mean leaves the mean unchanged.
📐 Worked Example — Identifying What Changes
Dataset: {4, 7, 9, 9, 12, 15, 20}. The value 4 is removed. How do the mean, median, mode, and range change?
MeanOld sum = 76, old mean = 76/7 ≈ 10.86. New sum = 72, new mean = 72/6 = 12. Mean increases.
MedianOld (7 values): 4th = 9. New sorted (6 values): {7,9,9,12,15,20}, median = (9+12)/2 = 10.5. Median increases.
ModeMode was 9 (appears twice). Still 9 after removal. Mode unchanged.
RangeOld: 20−4=16. New: 20−7=13. Range decreases.
Mean ↑, Median ↑, Mode unchanged, Range ↓

Changing Every Value by a Constant

OperationEffect on MeanEffect on MedianEffect on Range
Add k to every valueMean + kMedian + kNo change
Subtract k from every valueMean − kMedian − kNo change
Multiply every value by kMean × kMedian × kRange × k
Divide every value by kMean / kMedian / kRange / k
💡

Key insight: Adding or subtracting a constant shifts all values by the same amount — so the mean and median shift by the same amount, but the range (a difference) stays the same. Multiplying scales all values and the range equally.

Average Rate of Change

The average rate of change measures how much a quantity changes per unit of another quantity — typically how a value changes over time, distance, or another variable. It is the slope formula applied to real-world contexts.

Average Rate of Change = (Change in quantity) / (Change in time or input)
= (y₂ − y₁) / (x₂ − x₁)
// This is also the slope formula — rise over run
📐 Worked Example — Average Speed
A car travels 240 miles in 4 hours. What is its average speed?
01Average speed = Total distance / Total time
02= 240 miles / 4 hours = 60 mph
Average speed = 60 mph

The Average Speed Trap — Two Legs of a Journey

When a trip has two legs at different speeds, the average speed is NOT the arithmetic average of the two speeds. You must use: Total distance ÷ Total time.

📐 Worked Example — Two-Leg Speed Trap
Alicia drives 60 miles at 30 mph, then 60 miles at 60 mph. What is her average speed for the entire trip?
01Time for leg 1: 60 miles ÷ 30 mph = 2 hours
02Time for leg 2: 60 miles ÷ 60 mph = 1 hour
03Total distance: 60 + 60 = 120 miles
04Total time: 2 + 1 = 3 hours
05Average speed = 120 ÷ 3 = 40 mph
Average speed = 40 mph (NOT 45 mph — the arithmetic average)
Why Not 45 mph?

The 30 mph leg takes twice as long as the 60 mph leg (2 hours vs. 1 hour). Alicia spends more time driving slowly, so the slow speed has more influence on the average. The harmonic-mean intuition: average speed is always pulled toward the slower speed when equal distances are covered.

📐 Worked Example — Rate of Change from a Table
A plant's height (cm) is recorded over time: at week 0 it is 5 cm; at week 6 it is 23 cm. What is the average growth rate per week?
01Change in height: 23 − 5 = 18 cm
02Change in time: 6 − 0 = 6 weeks
03Average rate = 18 ÷ 6 = 3 cm/week
Average growth rate = 3 cm/week

Test Day Strategy

Top ACT Traps to Avoid

  • Average of averages: Never add group averages and divide — always go back to sums.
  • Average speed: For two-leg journeys, use Total distance ÷ Total time, never (v₁ + v₂)/2.
  • Forgetting to sort before finding the median — data on the ACT is almost never pre-sorted.
  • Even vs. odd count for median — always check whether n is even (average two middle values) or odd (one middle value).
  • Range only uses max and min — don't accidentally calculate something else.
  • Adding a value equal to the mean doesn't change the mean — know this cold for true/false style questions.

Problem-Type Decision Map

  • "Find the missing value given the average" → Sum = Mean × Count, subtract known sum.
  • "What score is needed to raise the average to X?" → Same approach: target sum minus current sum.
  • "Combined average of two groups" → Compute each sum, add them, divide by total count.
  • "What is the average speed for the whole trip?" → Total distance ÷ Total time.
  • "Effect of adding/removing a value" → Use new sum ÷ new count; re-sort for median.
  • "Weighted average" → Σ(value × weight) ÷ Σ(weights).

Quick Reference — All Formulas

ConceptFormulaKey Watch-out
MeanMean = Sum / CountConvert mean → sum as first step
Sum (from mean)Sum = Mean × CountUse this to find missing values
Median (odd n)Position = (n+1)/2Must sort data first
Median (even n)Average positions n/2 and n/2+1Average the two middle values
ModeMost frequent valueCan be none, one, or many
RangeMax − MinOnly two values needed
Weighted meanΣ(v × w) / Σ(w)Weights must sum to total weight
Combined mean(Sum₁ + Sum₂)/(n₁ + n₂)Never average the averages
Average rate of change(y₂ − y₁)/(x₂ − x₁)Same as slope formula
Average speedTotal distance / Total timeCompute time for each leg first
~4–7 questions per test High ROI — few formulas, many question types Appears on every ACT

Put It to the Test

You've covered every averages concept the ACT tests. Now build speed and accuracy with ACT-style questions. Start with Quiz 1 and progress through Quiz 3 — difficulty increases with each set.

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