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ACT Math, ACT Prep, Factors & Multiples

ACT Math Factors & Multiples Complete Study Guide

ACT Math: Factors & Multiples – Complete Study Guide | The School of Mathematics
ACT Math — Full Lesson

Factors & Multiples

A complete, test-focused breakdown of every Factors & Multiples concept on the ACT — from prime factorization and divisibility rules to GCF, LCM, and number theory applications — with worked examples, visual tools, and strategy notes for test day.

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Factors & Multiples — Definitions

These two concepts are mirrors of each other. Confusing them is one of the most common ACT errors — nail the distinction now.

Factor (divides INTO) A factor of n divides n evenly (no remainder).

Factors of 12: 1, 2, 3, 4, 6, 12
Because 12÷1=12, 12÷2=6, 12÷3=4, 12÷4=3, 12÷6=2, 12÷12=1 — all whole numbers, zero remainders.
Multiple (n divides INTO it) A multiple of n is n multiplied by any positive integer.

Multiples of 4: 4, 8, 12, 16, 20, …
Because 4×1=4, 4×2=8, 4×3=12, 4×4=16 — infinitely many multiples.
Memory Anchor

"Factors are Few, Multiples are Many."

Any integer has a finite number of factors but infinite multiples.
12 has exactly 6 factors. 12 has infinitely many multiples.

Factor Pairs

Factors always come in pairs that multiply to give the original number. List pairs systematically by testing divisors from 1 upward until you reach the square root — beyond that, pairs repeat.

📐 Worked Example — Listing All Factors
List all factors of 36.
01√36 = 6. Test divisors 1 through 6.
0236÷1 = 36 ✓ → pair (1, 36)
0336÷2 = 18 ✓ → pair (2, 18)
0436÷3 = 12 ✓ → pair (3, 12)
0536÷4 = 9 ✓ → pair (4, 9)
0636÷5 = 7.2 ✗ → not a factor
0736÷6 = 6 ✓ → pair (6, 6) — same number, count once
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36 (9 factors total)
💡

Square root shortcut: You only need to test divisors up to √n. Once you pass the square root, you're just finding the same pairs in reverse. This saves time on the ACT when n is large.

Key Properties to Know

  • Every integer is a factor of itself and has 1 as a factor.
  • Every positive integer is a multiple of 1 and a multiple of itself.
  • If a is a factor of b, then b is a multiple of a — and vice versa.
  • If a is a factor of b AND b is a factor of c, then a is a factor of c (transitivity).
  • If a and b are both factors of n, then (a+b) may or may not be a factor of n.

Divisibility Rules

Divisibility rules let you instantly check whether a number is divisible by another — without doing long division. On the ACT, these save significant time, especially on factor, GCF, and prime factorization problems.

Divisible byRuleExample — 2,184
2 Last digit is 0, 2, 4, 6, or 8 (even number) ✓ Last digit 4 → divisible
3 Sum of all digits is divisible by 3 ✓ 2+1+8+4 = 15, 15÷3=5 → divisible
4 Last two digits form a number divisible by 4 ✓ Last two: 84, 84÷4=21 → divisible
5 Last digit is 0 or 5 ✗ Last digit 4 → not divisible
6 Divisible by BOTH 2 AND 3 ✓ Even + digit sum 15 → divisible
7 No easy rule — divide directly or use prime factorization 2184 ÷ 7 = 312 → divisible
8 Last three digits form a number divisible by 8 ✓ Last three: 184, 184÷8=23 → divisible
9 Sum of all digits is divisible by 9 ✗ Digit sum = 15, 15÷9 not whole → not divisible
10 Last digit is 0 ✗ Last digit 4 → not divisible
11 Alternating sum of digits (left to right) is divisible by 11 or equals 0 ✓ 2−1+8−4 = 5 → not divisible (2,184÷11 = 198.5)
12 Divisible by BOTH 3 AND 4 ✓ Div by 3 and div by 4 → divisible by 12
📐 Worked Example — Using Divisibility Rules
Without dividing, determine which of 2, 3, 4, 5, 6, 9 are factors of 5,832.
÷2Last digit 2 → even ✓ Divisible by 2
÷35+8+3+2 = 18; 18÷3=6 ✓ Divisible by 3
÷4Last two digits: 32; 32÷4=8 ✓ Divisible by 4
÷5Last digit 2 → not 0 or 5 ✗ Not divisible by 5
÷6Divisible by 2 AND 3 ✓ Divisible by 6
÷9Digit sum = 18; 18÷9=2 ✓ Divisible by 9
Factors from that set: 2, 3, 4, 6, 9
💡

Combine rules: Divisibility by 6 = divisible by 2 AND 3. Divisibility by 12 = divisible by 3 AND 4. Divisibility by 15 = divisible by 3 AND 5. These compound rules often appear on the ACT without being explicitly stated.

Prime & Composite Numbers

Prime Number Has exactly two distinct positive factors: 1 and itself.

Examples: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29…
Composite Number Has more than two distinct positive factors — can be factored further.

Examples: 4, 6, 8, 9, 10, 12, 14, 15, 16…
Critical ACT Facts

1 is NEITHER prime nor composite — it has only one factor (itself).
2 is the ONLY even prime number — all other even numbers are composite.
All primes greater than 3 are of the form 6k±1 (but not all 6k±1 are prime).

Primes Under 100 — The Sieve of Eratosthenes

There are 25 prime numbers under 100. Memorize those under 50 — they appear constantly on the ACT.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
53
59
61
67
71
73
79
83
89
97

Blue = prime  ·  Gray = composite  ·  Light = 1 (neither)

Testing Whether a Number is Prime

To check if n is prime, test all prime divisors up to √n. If none divide evenly, n is prime.

📐 Worked Example — Primality Test
Is 127 prime?
01√127 ≈ 11.3 → test primes 2, 3, 5, 7, 11
02127÷2 = 63.5 ✗   127÷3: digit sum=10, not div by 3 ✗
03127÷5: doesn't end in 0 or 5 ✗   127÷7 = 18.1 ✗
04127÷11 = 11.5 ✗ → no prime divisor found
127 is prime ✓
⚠️

Common mistakes: Students often call 1 prime (it isn't) or assume 51 is prime (51 = 3×17) or 57 is prime (57 = 3×19). Always check divisibility by 3 using the digit-sum rule first — it catches many "prime-looking" composites.

Prime Factorization

The Fundamental Theorem of Arithmetic states that every integer greater than 1 can be written as a unique product of prime numbers (up to order). This representation is called the prime factorization.

Prime factorization is the engine behind GCF, LCM, factor counting, and many ACT number theory problems.

Factor Tree Method

Split the number into any two factors, then keep factoring each branch until all leaves are prime.

360
╱      ╲
4 × 90
↙↘         ↙↘
2 2    9 10
          ↙↘ ↙↘
       3 3 2 5
360 = 2³ × 3² × 5

Division Ladder Method

Divide repeatedly by the smallest prime that goes in evenly, working downward.

360 ÷ 2 = 180
180 ÷ 2 = 90
90 ÷ 2 = 45
45 ÷ 3 = 15
15 ÷ 3 = 5
5 ÷ 5 = 1
// Result: 2 × 2 × 2 × 3 × 3 × 5 = 2³ × 3² × 5
Standard Exponential Form

Always write the prime factorization with prime bases in ascending order with exponents:

n = p₁^a₁ × p₂^a₂ × p₃^a₃ × …

where p₁ < p₂ < p₃ < … are distinct primes and a₁, a₂, a₃ … are positive integers.

📐 Worked Example — Prime Factorization
Find the prime factorization of 1,260.
011260 ÷ 2 = 630 → 2 is a factor
02630 ÷ 2 = 315 → another factor of 2
03315 ÷ 3 = 105 (digit sum 3+1+5=9 ✓) → factor of 3
04105 ÷ 3 = 35 → another factor of 3
0535 ÷ 5 = 7 → factor of 5
067 is prime → done
1,260 = 2² × 3² × 5 × 7
💡

Use divisibility rules while factoring: Always test 2 first (is it even?), then 3 (digit sum), then 5 (ends in 0 or 5), then 7, then 11. This order minimizes the work on the ACT.

Greatest Common Factor (GCF)

The GCF (also called GCD — Greatest Common Divisor) of two or more numbers is the largest integer that divides all of them evenly.

Method 1 — List All Factors

Write out all factors of each number and find the largest one they share. Works well for small numbers.

📐 Worked Example — Listing Factors
Find GCF(24, 36)
01Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
02Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36
03Common factors: 1, 2, 3, 4, 6, 12 → largest is 12
GCF(24, 36) = 12

Method 2 — Prime Factorization (Best for Large Numbers)

Factor each number. Take the lowest power of every prime factor they share in common.

GCF = product of shared prime factors, each raised to its LOWEST exponent
📐 Worked Example — Prime Factorization Method
Find GCF(360, 504)
01360 = 2³ × 3² × 5
02504 = 2³ × 3² × 7
03Shared primes: 2 and 3
04Lowest powers: 2³ (min of 3,3) and 3² (min of 2,2)
05GCF = 2³ × 3² = 8 × 9 = 72
GCF(360, 504) = 72

Method 3 — Euclidean Algorithm (Fastest for Two Large Numbers)

Repeatedly replace the larger number with the remainder of dividing the larger by the smaller. Stop when the remainder is 0 — the last nonzero remainder is the GCF.

📐 Worked Example — Euclidean Algorithm
Find GCF(252, 180) using the Euclidean Algorithm
01252 = 1 × 180 + 72 → remainder 72
02180 = 2 × 72 + 36 → remainder 36
0372 = 2 × 36 + 0 → remainder 0 → STOP
04Last nonzero remainder = 36
GCF(252, 180) = 36
💡

When to use which method: Small numbers → list factors. Medium numbers → prime factorization. Large "ugly" numbers → Euclidean algorithm. On the ACT, prime factorization handles most cases since numbers are rarely huge.

GCF of Three or More Numbers

Use prime factorization: take the lowest exponent of each prime that appears in ALL numbers.

GCF(120, 180, 240):
120 = 2³ × 3 × 5
180 = 2² × 3² × 5
240 = 2⁴ × 3 × 5
GCF = 2² × 3¹ × 5¹ = 4 × 3 × 5 = 60

Least Common Multiple (LCM)

The LCM of two or more numbers is the smallest positive integer that is a multiple of all of them. Essential for adding fractions, scheduling problems, and cycle questions on the ACT.

Method 1 — List Multiples

Write out multiples of the larger number until you find one divisible by the smaller. Quick for small numbers.

📐 Worked Example — Listing Multiples
Find LCM(8, 12)
01Multiples of 12: 12, 24, 36, 48…
02Is 12 divisible by 8? 12÷8 = 1.5 ✗
03Is 24 divisible by 8? 24÷8 = 3 ✓
LCM(8, 12) = 24

Method 2 — Prime Factorization (Best Method)

Factor each number. Take the highest power of every prime factor that appears in any of the numbers.

LCM = product of ALL prime factors (from any number), each raised to its HIGHEST exponent
📐 Worked Example — Prime Factorization Method
Find LCM(18, 24, 30)
0118 = 2¹ × 3²
0224 = 2³ × 3¹
0330 = 2¹ × 3¹ × 5¹
04All primes that appear: 2, 3, 5
05Highest powers: 2³ (from 24), 3² (from 18), 5¹ (from 30)
06LCM = 2³ × 3² × 5 = 8 × 9 × 5 = 360
LCM(18, 24, 30) = 360
⚠️

GCF vs. LCM confusion trap: GCF uses the lowest exponent of shared primes. LCM uses the highest exponent of all primes. Students frequently swap these. A memory trick: GCF → Go low. LCM → Lift high.

The GCF × LCM Relationship

Fundamental Theorem

For any two positive integers a and b:

GCF(a, b) × LCM(a, b) = a × b

This means: if you know any three of the four values, you can find the fourth instantly.

📐 Worked Example — Using the Relationship
The GCF of two numbers is 12 and their product is 1,440. Find their LCM.
01Formula: GCF × LCM = a × b
0212 × LCM = 1,440
03LCM = 1,440 ÷ 12 = 120
LCM = 120
📐 Worked Example — Finding GCF from LCM
Two numbers are 36 and 48. Their LCM is 144. Find the GCF.
01GCF × LCM = a × b → GCF × 144 = 36 × 48
0236 × 48 = 1,728
03GCF = 1,728 ÷ 144 = 12
GCF(36, 48) = 12 ✓ (verify: 36 = 2²×3², 48 = 2⁴×3, GCF = 2²×3 = 12)

Finding Two Numbers from GCF and LCM

If you know the GCF and LCM of two numbers, you can find candidate pairs. Write each number as GCF × (some factor), where the two "some factors" must be coprime (GCF of 1) and their product = LCM ÷ GCF.

📐 Worked Example — Reconstruct the Numbers
The GCF of two numbers is 6 and their LCM is 60. What could the two numbers be?
01Write each number as 6k and 6m where GCF(k, m) = 1
02LCM = 6km → 60 = 6km → km = 10
03Coprime pairs (k, m) with km=10: (1,10) or (2,5)
04So numbers are: 6×1=6 and 6×10=60, OR 6×2=12 and 6×5=30
Possible pairs: (6, 60) or (12, 30)

Counting the Number of Factors

The ACT sometimes asks how many factors a number has without asking you to list them. There is a direct formula using prime factorization.

Factor Counting Formula

If n = p₁^a₁ × p₂^a₂ × p₃^a₃ × …

Then the total number of factors of n =
(a₁ + 1)(a₂ + 1)(a₃ + 1) …

Add 1 to each exponent, then multiply those results together.

📐 Worked Example — Counting Factors
How many positive factors does 360 have?
01Prime factorization: 360 = 2³ × 3² × 5¹
02Exponents: 3, 2, 1
03Add 1 to each: (3+1)(2+1)(1+1) = 4 × 3 × 2
04Multiply: 4 × 3 × 2 = 24
360 has 24 positive factors
📐 Worked Example — Perfect Squares Have Odd Factor Counts
Why does 36 have an odd number of factors?
0136 = 2² × 3² → factor count = (2+1)(2+1) = 9
02Factors: 1,2,3,4,6,9,12,18,36 → confirmed 9 factors
03The factor 6 pairs with itself (6×6=36) → creates one unpaired factor
Perfect squares always have an ODD number of factors
💡

ACT application: "Which of the following has exactly 6 factors?" → You need n with (a+1)(b+1)… = 6. Options: exponent pattern 5 → gives 6 (one prime, e.g. p⁵), or exponent pattern 2,1 → gives (2+1)(1+1)=6 (two primes, e.g. p²×q). Check both patterns quickly.

Finding Numbers with a Specific Factor Count

Target Factor CountExponent PatternSmallest Example
2 factorsn = p¹2 (prime)
3 factorsn = p²4 = 2²
4 factorsn = p³ or p¹×q¹8 or 6
6 factorsn = p⁵ or p²×q¹32 or 12
8 factorsn = p⁷ or p³×q¹ or p¹×q¹×r¹128 or 24 or 30
Odd factor countAll exponents must be evenn must be a perfect square

ACT Applications & Word Problems

Tiling / Cutting / Splitting Problems → GCF

Whenever a problem asks for the largest equal pieces, the fewest cuts, or the biggest tile that fits without gaps, the answer is a GCF.

📐 Worked Example — Tiling Problem
A rectangular floor is 84 cm by 60 cm. What is the largest square tile (with whole-number side length in cm) that can cover the floor exactly with no cutting?
01The tile side must divide both 84 and 60 evenly → we need GCF(84, 60)
0284 = 2² × 3 × 7    60 = 2² × 3 × 5
03GCF = 2² × 3 = 12
Largest square tile: 12 cm × 12 cm

Scheduling / Cycle Problems → LCM

Whenever a problem asks when will two events coincide again, or what is the earliest time both occur together, the answer is an LCM.

📐 Worked Example — Cycle / Scheduling Problem
Bus A passes a stop every 12 minutes. Bus B passes the same stop every 20 minutes. If both pass at 8:00 AM, when is the next time both buses pass together?
01Find LCM(12, 20): 12 = 2²×3, 20 = 2²×5
02LCM = 2² × 3 × 5 = 60 minutes
03Next meeting: 8:00 AM + 60 minutes = 9:00 AM
Both buses pass together again at 9:00 AM

Distributing / Grouping Problems → GCF

When you want to split multiple quantities into the largest equal groups with nothing left over, use GCF.

📐 Worked Example — Equal Groups
A teacher has 48 pencils and 36 notebooks to distribute equally among students, with no items left over. What is the maximum number of students?
01Students must divide both 48 and 36 → GCF(48, 36)
0248 = 2⁴ × 3    36 = 2² × 3²
03GCF = 2² × 3 = 12
04Each student gets: 48÷12 = 4 pencils and 36÷12 = 3 notebooks
Maximum 12 students

Smallest Number Satisfying Multiple Divisibility Conditions → LCM

📐 Worked Example — Divisibility Conditions
What is the smallest positive integer divisible by 4, 6, and 10?
014 = 2²    6 = 2×3    10 = 2×5
02LCM = 2² × 3 × 5 = 60
Smallest integer: 60

"Remainder" Problems — A Hidden Divisibility Pattern

Problems of the type "when divided by 5 leaves remainder 2, when divided by 7 leaves remainder 2" — the common remainder clue means the answer is LCM + remainder.

📐 Worked Example — Remainder Pattern
Find the smallest positive integer that leaves a remainder of 3 when divided by 4, 6, or 9.
01The number minus 3 must be divisible by 4, 6, and 9
02Find LCM(4, 6, 9): 4=2², 6=2×3, 9=3² → LCM = 2²×3² = 36
03Smallest such number = 36 + 3 = 39
04Check: 39÷4=9R3 ✓ 39÷6=6R3 ✓ 39÷9=4R3 ✓
Answer: 39

Test Day Strategy

Top ACT Traps to Avoid

  • 1 is not prime. It has only one factor — itself. Every ACT that asks about primes tries to catch you here.
  • 2 is prime — the only even prime. Don't exclude it.
  • Swapping GCF and LCM: GCF is always ≤ both numbers; LCM is always ≥ both.
  • For GCF, use the lowest exponents of shared primes. For LCM, use the highest exponents of all primes.
  • Forgetting to check if a "prime-looking" number like 51 or 91 is actually composite (51=3×17, 91=7×13).
  • Answering "how many factors" by listing instead of using the formula — wastes time on large numbers.

Decision Framework

  • "Largest equal piece / group" → GCF
  • "Next time both/all coincide" → LCM
  • "Smallest divisible by all" → LCM
  • "Fewest cuts with no waste" → GCF
  • "How many factors does n have?" → factor-count formula
  • "Is n prime?" → test primes up to √n

Must-Know Quick Reference

ConceptFormula / RuleKey Detail
GCF (prime factorization)Shared primes, LOWEST exponentsGCF ≤ min(a, b)
LCM (prime factorization)All primes, HIGHEST exponentsLCM ≥ max(a, b)
GCF × LCM relationshipGCF(a,b) × LCM(a,b) = a × bWorks for 2 numbers only
Number of factors(a₁+1)(a₂+1)… from n=p₁^a₁×p₂^a₂…Odd count → perfect square
Divisibility by 3Sum of digits divisible by 3Works for 9 too (sum div by 9)
Divisibility by 6Divisible by 2 AND 3Compound rule
Primality testTest prime divisors up to √nIf none found → prime
Primes under 202, 3, 5, 7, 11, 13, 17, 198 primes — memorize all
~4–7 questions per test High ROI — few rules, many questions Appears on every ACT

Put It to the Test

You've covered every concept. Lock it in with ACT-style timed questions. Start with Quiz 1 and progress through Quiz 3 — each set increases in difficulty and problem variety.

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