SAT Math Practice: Problem-Solving & Data Analysis (7 Step-by-Step Explanations)
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SAT Math · Problem-Solving & Data Analysis

SAT Math Practice: Problem-Solving & Data Analysis

Problem-Solving and Data Analysis is one of the four major content areas on the Digital SAT Math section, and it's built almost entirely out of realistic scenarios dressed up in numbers: unit rates and unit conversions, ratios and proportions, percentages layered on top of fractions, work rate problems, and age word problems that require setting up a relationship between two people's ages at two different points in time. None of these individually require advanced algebra, but they do require translating a wordy setup into a clean equation without losing track of any detail along the way.

A few strategies make these problems far more manageable. For any rate or ratio problem, find the rate per unit first (miles per gallon, desks per carpenter per day, dollars per pound) before trying to scale up to the specific quantities the question asks about, since jumping straight to the final numbers is where most errors creep in. For "fraction of a fraction" problems, like a fraction of the girls at a camp under a certain height, work through the fractions one at a time rather than trying to combine them mentally in a single step. For work rate problems, remember that the total amount of work done equals the rate per worker per day, multiplied by the number of workers, multiplied by the number of days, so setting up "rate × workers × days = total work" for both scenarios in the problem lets you solve for whatever's missing. And for age problems, always define each person's age using the same variable at the same point in time, then carefully add the same number of years to both sides when the problem shifts to "in five years" or similar.

Below are 7 SAT Math-style Problem-Solving and Data Analysis practice problems covering unit rates, ratios and proportions, work rate problems, and age word problems. Work through each problem, select your answer, and check whether you got it right. Every problem includes a complete, step-by-step explanation. Once you've worked through these, keep building your skills with the free SAT Math Question Bank, with 2,500+ more digital SAT practice problems and instant explanations.

1
A unit rate and division word problem

Sara's car holds 40 gallons of fuel. If she drives 120,000 miles at 30 miles per gallon, how many full tanks of gas will she use through her journey if she starts with a full tank?

Full Explanation

First find the total gallons of fuel needed for the whole trip: 120,000 miles ÷ 30 miles/gallon = 4,000 gallons.

Since the tank holds 40 gallons, divide the total gallons needed by the tank capacity to find how many full tanks that represents: 4,000 ÷ 40.

= 100. The correct answer is C.

2
Writing an expression for a unit price

If three pounds of apples cost $5.40, how much will p pounds of apples cost?

Full Explanation

First find the price per pound: $5.40 ÷ 3 pounds = 5.40/3 dollars per pound.

To find the cost of p pounds, multiply the price per pound by p.

(5.40/3)p. The correct answer is B.

3
A fraction of a fraction

There are 48 students at a math camp. If five-eighths of the students are girls and two-fifths of the girls are under 5 feet tall, how many girls are under 5 feet tall?

Full Explanation

First find the number of girls: (5/8) × 48 = 30 girls.

Then find how many of those girls are under 5 feet tall: (2/5) × 30.

= 12. The correct answer is B.

4
Matching ratios between two groups

At Happy Paws, 70% of the 30 cats have green eyes. The fraction of rabbits at the store with yellow eyes is equal to the fraction of cats at the store with yellow eyes. What is the ratio of rabbits that have yellow eyes, if the cats only have green and yellow eyes?

Full Explanation

Since the cats only have green and yellow eyes, and 70% have green eyes, the remaining 30% must have yellow eyes.

The fraction of cats with yellow eyes is 30% = 3/10.

Since the fraction of rabbits with yellow eyes is given to be equal to this same fraction, the ratio of rabbits with yellow eyes is also 3/10.

The correct answer is B.

5
A work rate problem

8 electricians take 4 days to install 64 outlets. How many days will it take for 10 electricians to complete 100 outlets, if all electricians work at the same rate?

Full Explanation

First find the rate per electrician per day: 64 outlets ÷ (8 electricians × 4 days) = 64/32 = 2 outlets per electrician per day.

Set up the same relationship for the second scenario, with d representing the unknown number of days: 10 electricians × 2 outlets/electrician/day × d days = 100 outlets.

20d = 100 → d = 5. The correct answer is B.

5 down, 2 to go. Almost there.

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6
A perimeter word problem with unit conversion

A square garden has a side length of 3 feet. If a fence, which is 24 inches away from either side of the garden, is created, what is the perimeter of the fence created, in inches? (1 foot = 12 inches)

Full Explanation

First convert the garden's side length to inches: 3 feet × 12 = 36 inches.

Since the fence is 24 inches away from the garden on both sides of each edge, the new (larger) square's side length is the original side plus twice the offset: 36 + 2(24) = 36+48 = 84 inches.

The perimeter of a square is four times its side length: 4 × 84.

= 336 inches. The correct answer is C.

7
An age word problem with a future ratio

Marcus's age is 4 times his son's age. In six years, the ratio of Marcus's age to his son's age would be 5:2. How old is the son now?

Full Explanation

Let s represent the son's current age. Since Marcus's age is 4 times his son's, Marcus's current age is 4s.

In six years, the son will be s+6 and Marcus will be 4s+6. Set up the given ratio as an equation: (4s+6)/(s+6) = 5/2.

Cross-multiply: 2(4s+6) = 5(s+6) → 8s+12 = 5s+30.

3s = 18 → s = 6. The correct answer is B.

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