Mini Exam 5 — Timed Mini Exams
Practice Mini Exam 5 — Timed Mini Exams on The School of Mathematics (Timed Mini Exams) with 10 scored questions. This set covers problems such as: “At what point in the interval [0,2] is the rate of change of f(x)=\cos x equal to its average rate of chang…”; “Suppose \int_1^4 (f(x)+k)\,dx=9 where k is a constant. Then \int_1^4 f(x)\,dx equals:”; “If \int_{-2}^5 f(x)\,dx=7 then \int_{-3}^4 f(x+1)\,dx= ?”. Work carefully, check explanations for misses, then retake to track improvement before test day.
Questions in this quiz (10)
At what point in the interval $$[0,2]$$ is the rate of change of $$f(x)=\cos x$$ equal to its average rate of change on the interval?
- $$0.785$$
- $$1.047$$
- $$1.215$$
- $$1.571$$
Suppose $$\int_1^4 (f(x)+k)\,dx=9$$ where $$k$$ is a constant. Then $$\int_1^4 f(x)\,dx$$ equals:
- $$9-3k$$
- $$9-k$$
- $$9$$
- $$9+k$$
If $$\int_{-2}^5 f(x)\,dx=7$$ then $$\int_{-3}^4 f(x+1)\,dx=$$?
- $$-7$$
- $$6$$
- $$7$$
- $$8$$
If $$f(u)=\tan^{-1}(3u^2)$$ and $$g(u)=e^{2u}$$ then the derivative of $$f(g(u))$$ is:
- $$\frac{6ue^{2u}}{1+9u^4}$$
- $$\frac{6e^{2u}}{1+9e^{4u}}$$
- $$\frac{6e^{4u}}{1+9e^{4u}}$$
- $$\frac{12e^{2u}}{1+9e^{4u}}$$
The region bounded by $$y=e^{2x}$$, $$y=1$$, and $$x=1$$ is rotated about the $$x$$-axis. The volume of the solid generated is given by the integral:
- $$\pi\int_0^1 e^{4x}\,dx$$
- $$2\pi\int_1^e (1-\ln y)(y-1)\,dy$$
- $$\pi\int_0^1 (e^{4x}-1)\,dx$$
- $$\pi\int_0^1 (e^{2x}-1)^2\,dx$$
Let $$f(x)=\int_{0}^{x}(2-\sin^{2}t)dt$$ for $$0\leq x\leq 2\pi$$. On which interval is $$f$$ increasing?
- $$0$$<$$x$$<$$\pi$$
- $$0.785$$<$$x$$<$$5.498$$
- $$\pi$$<$$x$$<$$2\pi$$
- $$0$$<$$x$$<$$2\pi$$
An ellipse has major axis $$16$$ and minor axis $$8$$. Rounded to the nearest integer, the maximum area of an inscribed rectangle is:
- $$32$$
- $$48$$
- $$64$$
- $$80$$
The average value of $$y=x\ln x$$ on the interval $$1\le x\le 3$$ is:
- $$1.10$$
- $$1.47$$
- $$1.65$$
- $$2.00$$
Shown is the graph of $$f(x)=\frac{4}{x^{2}+1}$$.Let $$H(x)=\int_{0}^{x}f(t)dt$$. The local linearization of $$H$$ at $$x=1$$ is
- $$y=2x$$
- $$y=-2x-4$$
- $$y=2x+\pi-2$$
- $$y=-2x+\pi+2$$
In a protected lake, the fish population increases at a rate$$\frac{dP}{dt}=k(800-P)$$where $$P(t)$$ represents the population at $$t$$ years. If $$200$$ fish were initially placed in the lake and the population grew to $$400$$ in $$4$$ years, how many fish will there be after $$8$$ years?
- $$533$$
- $$560$$
- $$600$$
- $$640$$
Related quizzes
Frequently asked questions
How many questions are in Mini Exam 5 — Timed Mini Exams?
This practice set includes 10 questions. Finish in one sitting when possible, then review incorrect answers before retaking.
What topic does Mini Exam 5 — Timed Mini Exams cover?
Mini Exam 5 — Timed Mini Exams focuses on Timed Mini Exams. Questions follow exam-style wording and difficulty so you can practice the skills tested on major Timed Mini Exams assessments. These are practice materials, not official exam questions.
How is Mini Exam 5 — Timed Mini Exams scored?
Your score is the percentage of correct answers. A typical passing score is 80%. After you finish, review each miss with the available explanations on The School of Mathematics.
Comments
Share your thoughts or ask a question. Comments are moderated before publication.
Loading comments…