Mini Exam 5 — Timed Mini Exams
AP Calculus BC Timed Mini Exams Mini Exam 5
Duration
25 min
Questions
9
Category
Timed Mini Exams
Questions in this quiz (9)
If $$x=\ln t$$ and $$y=e^{3t}$$, then $$\frac{dy}{dx}=$$
- $$3e^{3t}$$
- $$\frac{3e^{3t}}{t}$$
- $$3te^{3t}$$
- $$\frac{te^{3t}}{3}$$
The function $$y=\frac{(x-1)^2}{x^2-4x+3}$$ has a local minimum at $$x=$$
- $$0$$
- $$1$$
- $$2$$
- The function has no local minimum.
Evaluate $$\frac{d}{dx}\left(e^{2x}\ln(\sin e^x)\right)$$
- $$2e^{2x}\ln(\sin e^x)+e^{3x}\cot(e^x)$$
- $$e^{2x}\ln(\sin e^x)+e^{3x}\cot(e^x)$$
- $$2e^{2x}\ln(\sin e^x)+e^{2x}\cot(e^x)$$
- $$e^{3x}\cot(e^x)$$
If $$f(x)=\frac{\cos x}{x^2}$$ then $$f'(\pi)=$$
- $$-\frac{1}{\pi^2}$$
- $$\frac{1}{\pi^2}$$
- $$-\frac{2}{\pi^3}$$
- $$\frac{2}{\pi^3}$$
Evaluate $$\int_2^{\infty}\frac{\ln x}{x^3}\,dx$$
- $$\frac{\ln2+1}{4}$$
- $$\frac{\ln2}{4}$$
- $$\frac{2\ln2+1}{16}$$
- It diverges
Evaluate $$\int x\tan^2x\,dx$$
- $$x\tan x+\ln|\cos x|+C$$
- $$x\tan x+\ln|\cos x|-\frac{x^2}{2}+C$$
- $$x\tan x-\ln|\sec x+\tan x|+C$$
- $$x\tan x+\ln|\sec x+\tan x|+C$$
Evaluate $$\lim_{x\to1}\frac{(\ln x)^3}{x^2-1}$$
- $$0$$
- $$1$$
- $$\frac{1}{2}$$
- It does not exist
What is the approximation of the value of $$\sin(1)$$ obtained by using the fifth-degree Taylor polynomial about $$x=0$$ for $$\sin x$$?
- $$1-\frac{1}{6}+\frac{1}{120}$$
- $$1-\frac{1}{2}-\frac{1}{24}$$
- $$1-\frac{1}{6}-\frac{1}{120}$$
- $$1-\frac{1}{2}+\frac{1}{120}$$
A particle moves on a plane curve so that at any time $$t>0$$ its position is defined by $$x(t)=t^2+1,\quad y(t)=\frac{t^3+2}{t}$$ The acceleration vector of the particle at $$t=1$$ is
- $$\langle2,1\rangle$$
- $$\langle2,2\rangle$$
- $$\langle2,6\rangle$$
- $$\langle3,1\rangle$$
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