GED Math: Systems of Equations
Systems of equations model situations with two unknown quantities and two pieces of information. Steps: (1) define two variables (say x and y) with units; (2) write one equation from each piece of information, often a total count and a total value; (3) solve by substitution or elimination; (4) answer the exact question that was asked, with units, and check against the story. A typical pair is: (number of items) x + y = total, and (price × number) 8x + 5y = total cost.
1. What Is a System of Equations? Checking a Solution
A system of linear equations is two (or more) linear equations that use the same variables. Each equation is a straight line, so solving the system means finding the values of x and y that make both equations true at once. That solution is the point where the two lines intersect, written as an ordered pair (x, y). There are several ways to solve a system: graphing (draw both lines and read the intersection), substitution (solve one equation for a variable and put it into the other), and elimination (add or subtract equations to cancel a variable). Whatever method you use, you can always check an answer by substituting it into both original equations. Test tip: when a question asks whether a point is a solution, you do not need to solve; just test the point in both equations.
Worked Example: Is (3, 1) a solution of x + y = 4 and 2x − y = 5?
First equation: 3 + 1 = 4, true. Second equation: 2(3) − 1 = 5, true. Both hold, so (3, 1) is a solution.
1. Is (3, 1) a solution of the system?
x + y = 4
2x − y = 5
Explanation: Substitute into both equations. A point is a solution only if it makes both true. Here the first equation is true and the second is true.
2. Is (5, 1) a solution of the system?
x + y = 6
x − y = 2
Explanation: Substitute into both equations. A point is a solution only if it makes both true. Here the first equation is true and the second is false.
3. Is (2, 4) a solution of the system?
3x + y = 10
x − 2y = −6
Explanation: Substitute into both equations. A point is a solution only if it makes both true. Here the first equation is true and the second is true.
4. Is (2, 3) a solution of the system?
x + 2y = 8
2x − y = 2
Explanation: Substitute into both equations. A point is a solution only if it makes both true. Here the first equation is true and the second is false.
5. The solution of a system of two linear equations is:
Explanation: The solution is the ordered pair that satisfies both equations, which is the intersection point of the lines.
6. Which is NOT a method for solving a system of linear equations?
Explanation: Graphing, substitution and elimination are standard methods. Taking square roots is not a method for linear systems.
2. Solving a System by Graphing
To solve by graphing: (1) make a T-chart for each equation by finding two ordered pairs (use x = 0 to find y, then y = 0 to find x, or any easy values); (2) plot the points and draw both lines on the same grid; (3) find the point of intersection and write it as (x, y). Always check by substituting that point into both equations, because reading a graph can be off by a small amount. Graphing is a good method when the answer is a whole-number point, and when a question already shows the graph, simply read the crossing point.
Worked Example: Solve 2x + y = 4 and 5x + y = 7 by graphing.
For 2x + y = 4: (0, 4) and (2, 0). For 5x + y = 7: (0, 7) and (1, 2). Draw both lines: they cross at (1, 2). Check: 2(1) + 2 = 4 and 5(1) + 2 = 7.
1. What is the solution of the system graphed?
Explanation: The lines cross at P (2, 3). Check: y = x + 1 gives 3 = 2 + 1, and y = −x + 5 gives 3 = −2 + 5.
2. What is the solution of the system graphed?
Explanation: The lines cross at (2, 1). Check: −2 + 3 = 1 and 2(2) − 3 = 1.
3. Complete the T-chart for 3x + y = 9. What is y when x = 0?
Explanation: 3(0) + y = 9, so y = 9.
4. Complete the T-chart for 3x + y = 9. What is x when y = 0?
Explanation: 3x + 0 = 9, so x = 3.
5. Which two points can you use to graph 4x + 2y = 10?
Explanation: At x = 0: 2y = 10, so y = 5. At y = 0: 4x = 10, so x = 2.5.
6. The lines y = 3x − 15 and x + y = 13 intersect where x = 7 (checked by T-charts). What is the solution?
Explanation: At x = 7: y = 3(7) − 15 = 6, and 7 + 6 = 13 ✓. The solution is (7, 6).
3. Solving a System by Substitution
Substitution works best when one equation already has a variable alone, or can easily be solved for one. Steps: (1) solve one equation for y (or x); (2) substitute that expression into the other equation, which leaves one equation with one variable; (3) solve for that variable; (4) substitute the value back into either equation to find the second variable; (5) write the solution as (x, y) and check it in both equations. Be careful to put parentheses around the substituted expression so negative signs are distributed correctly. Test tip: make sure you substitute into the other equation; substituting back into the same equation just gives 0 = 0 or a true statement with no information.
Worked Example: Solve 6x + 3y = 12 and 5x + y = 7.
Solve the first for y: 3y = 12 − 6x, so y = 4 − 2x. Substitute into the second: 5x + (4 − 2x) = 7, so 3x + 4 = 7, 3x = 3, x = 1. Then y = 4 − 2(1) = 2. The solution is (1, 2).
1. Solve the system by substitution. Write the answer as an ordered pair.
x + y = 13
3x − y = 15
Explanation: Solving gives x = 7 and y = 6. Check in both equations: x + y = 13 gives 1(7) + (1)(6) = 13; the second equation also holds. The solution is (7, 6).
2. Solve the system by substitution. Write the answer as an ordered pair.
7x − y = 22
4x + 2y = 10
Explanation: Solving gives x = 3 and y = −1. Check in both equations: 7x − y = 22 gives 7(3) + (-1)((−1)) = 22; the second equation also holds. The solution is (3, −1).
3. Solve the system by substitution. Write the answer as an ordered pair.
x + y = 9
2x − 3y = 8
Explanation: Solving gives x = 7 and y = 2. Check in both equations: x + y = 9 gives 1(7) + (1)(2) = 9; the second equation also holds. The solution is (7, 2).
4. Solve the system by substitution. Write the answer as an ordered pair.
5x − 2y = −26
3x − y = −15
Explanation: Solving gives x = −4 and y = 3. Check in both equations: 5x − 2y = −26 gives 5((−4)) + (-2)(3) = -26; the second equation also holds. The solution is (−4, 3).
5. Solve the system by substitution. Write the answer as an ordered pair.
10x − y = −6
4x − y = 0
Explanation: Solving gives x = −1 and y = −4. Check in both equations: 10x − y = −6 gives 10((−1)) + (-1)((−4)) = -6; the second equation also holds. The solution is (−1, −4).
6. Solve the system by substitution. Write the answer as an ordered pair.
x + 2y = 11
x − y = 2
Explanation: Solving gives x = 5 and y = 3. Check in both equations: x + 2y = 11 gives 1(5) + (2)(3) = 11; the second equation also holds. The solution is (5, 3).
7. To solve y = 2x + 1 and 3x + y = 11 by substitution, which equation results after substituting?
Explanation: Replace y in the second equation with 2x + 1: 3x + (2x + 1) = 11.
8. Solve x + 2y = 11 for x.
Explanation: Subtract 2y from both sides: x = 11 − 2y.
4. Solving a System by Elimination
Elimination is a third method that often works faster when both equations are written as ax + by = c. The idea is to add or subtract the equations so that one variable cancels. Steps: (1) line the equations up so the x-terms, y-terms and constants are in columns; (2) if no variable has matching or opposite coefficients, multiply one or both equations by a number to create them; (3) add the equations if the coefficients are opposites (like +3y and −3y), or subtract if they are the same; (4) solve for the remaining variable; (5) substitute back to find the other variable and check in both equations.
Worked Example: Solve x + y = 9 and 2x − 3y = 8.
Multiply the first equation by 3: 3x + 3y = 27. Add it to the second: 5x = 35, so x = 7. Then 7 + y = 9, so y = 2. The solution is (7, 2).
1. Solve the system by elimination. Write the answer as an ordered pair.
x + y = 10
x − y = 2
Explanation: Solving gives x = 6 and y = 4. Check in both equations: x + y = 10 gives 1(6) + (1)(4) = 10; the second equation also holds. The solution is (6, 4).
2. Solve the system by elimination. Write the answer as an ordered pair.
2x + 3y = 16
2x − y = 0
Explanation: Solving gives x = 2 and y = 4. Check in both equations: 2x + 3y = 16 gives 2(2) + (3)(4) = 16; the second equation also holds. The solution is (2, 4).
3. Solve the system by elimination. Write the answer as an ordered pair.
3x + 2y = 7
5x − 2y = 17
Explanation: Solving gives x = 3 and y = −1. Check in both equations: 3x + 2y = 7 gives 3(3) + (2)((−1)) = 7; the second equation also holds. The solution is (3, −1).
4. Solve the system by elimination. Write the answer as an ordered pair.
x + y = 9
2x − 3y = 8
Explanation: Solving gives x = 7 and y = 2. Check in both equations: x + y = 9 gives 1(7) + (1)(2) = 9; the second equation also holds. The solution is (7, 2).
5. Solve the system by elimination. Write the answer as an ordered pair.
4x + 3y = −1
2x + 5y = −11
Explanation: Solving gives x = 2 and y = −3. Check in both equations: 4x + 3y = −1 gives 4(2) + (3)((−3)) = -1; the second equation also holds. The solution is (2, −3).
6. To eliminate y in 3x + 2y = 12 and 5x − 2y = 4, you should:
Explanation: The y-coefficients are +2 and −2 (opposites), so adding cancels y: 8x = 16.
7. Add 3x + 2y = 12 and 5x − 2y = 4. What is x?
Explanation: Adding gives 8x = 16, so x = 2.
5. Special Systems: Parallel, Same Line, and Intersecting Lines
Not every system has exactly one solution. Rewrite both equations in slope-intercept form y = mx + b and compare. If the slopes are different, the lines cross exactly once: one solution. If the slopes are the same but the y-intercepts differ, the lines are parallel and never meet: no solution (algebra produces a false statement like 0 = 5). If the slopes and the y-intercepts are both the same, the equations describe the same line: infinitely many solutions (algebra produces a true statement like 0 = 0). This lets you answer “does this line intersect that line?” without graphing: a line with a different slope always intersects.
Worked Example: How many solutions does y = 2x + 1, y = 2x − 3 have?
Both slopes are 2, but the y-intercepts (1 and −3) differ. The lines are parallel: no solution.
1. How many solutions does the system graphed have?
Explanation: The lines have the same slope and different intercepts, so they are parallel and never meet.
2. How many solutions does this system have?
y = 3x + 2
2y = 6x + 4
Explanation: Dividing the second equation by 2 gives y = 3x + 2, the same line, so every point on it is a solution.
3. How many solutions does this system have?
y = 4x + 2
y = −4x + 2
Explanation: The slopes (4 and −4) differ, so the lines cross once (at (0, 2)).
4. Which equation is the equation of a line that intersects y = 4x + 2?
Explanation: Only y = −4x + 2 has a different slope. The others have slope 4 and are parallel (or the same line), so they do not intersect at exactly one point.
5. Where does the line y = −2 intersect the line 3y = 2x + 3?
Explanation: Substitute y = −2: −6 = 2x + 3, so 2x = −9 and x = −9/2. The point is (−9/2, −2).
6. Where does y = x intersect y = −x?
Explanation: Set x = −x, so 2x = 0 and x = 0, y = 0. They intersect at the origin.
6. Systems in Word Problems
Systems of equations model situations with two unknown quantities and two pieces of information. Steps: (1) define two variables (say x and y) with units; (2) write one equation from each piece of information, often a total count and a total value; (3) solve by substitution or elimination; (4) answer the exact question that was asked, with units, and check against the story. A typical pair is: (number of items) x + y = total, and (price × number) 8x + 5y = total cost.
Worked Example: A theater sells 120 tickets for $840. Adult tickets cost $8 and child tickets cost $5. How many adult tickets were sold?
Let a = adults and c = children. a + c = 120 and 8a + 5c = 840. From the first, c = 120 − a. Then 8a + 5(120 − a) = 840, so 3a + 600 = 840, a = 80. 80 adult tickets were sold.
1. A theater sells 150 tickets for $1,020. Adult tickets cost $8 and child tickets cost $5. How many child tickets were sold?
Explanation: a + c = 150 and 8a + 5c = 1020. Then 3a + 750 = 1020, a = 90, so c = 60.
2. Two numbers add to 25 and differ by 7. What is the larger number?
Explanation: x + y = 25 and x − y = 7. Adding gives 2x = 32, so x = 16.
3. A shop sells pens for $2 and notebooks for $5. Customer A buys 3 pens and 2 notebooks. Which equation gives the total cost T?
Explanation: Total cost is price times quantity for each item: 2(3) + 5(2) = 16.
4. A gym charges a $40 sign-up fee plus $20 per month. A second gym charges no fee and $30 per month. After how many months do the two plans cost the same?
Explanation: 40 + 20m = 30m, so 40 = 10m and m = 4.
5. A rectangle has perimeter 40 and its length is 4 more than its width. What is the width?
Explanation: 2l + 2w = 40 and l = w + 4. Then 2(w + 4) + 2w = 40, so 4w + 8 = 40 and w = 8.
6. The sum of two numbers is 18 and twice the first minus the second is 9. What is the first number?
Explanation: x + y = 18 and 2x − y = 9. Adding gives 3x = 27, so x = 9.
Common Mistakes to Avoid
- Finding only x and forgetting to find y. A solution is an ordered pair.
- Writing the pair as (y, x) instead of (x, y).
- Substituting into the same equation you solved instead of the other one.
- Forgetting parentheses when substituting, so a minus sign is not distributed: 5x + (4 − 2x) is not 5x + 4 − 2x unless you keep the sign correct.
- When eliminating, adding equations when the coefficients are the same (you should subtract) or subtracting only part of an equation.
- Multiplying only one side of an equation when scaling it.
- Checking a point in only one equation. It must satisfy both.
- Assuming every system has one solution. Same slope can mean no solution or infinitely many.
Frequently Asked Questions
What is a system of linear equations?
Two or more linear equations with the same variables. Solving it means finding the values that make all the equations true.
What is the solution of a system?
The ordered pair (x, y) where the lines intersect.
How do I solve a system by substitution?
Solve one equation for a variable, substitute it into the other equation, solve, then substitute back to find the second variable.
How do I solve a system by elimination?
Line up the equations, make a variable's coefficients opposite, add the equations to cancel it, solve, and substitute back.
How do I know if a system has no solution?
If both equations have the same slope but different y-intercepts, the lines are parallel and there is no solution.
How can I check my answer?
Substitute the ordered pair into both original equations. Both must be true.
Where can I practice more problems like these?
The GED Math practice in the GED Math QBank gives you more practice on this topic, and you can browse every other topic in the full GED Math QBank.