"Probability and conditional probability" is an officially named skill in College Board's Problem-Solving and Data Analysis domain, and it's tested through everything from simple single-event probability to reading two-way frequency tables. This free, complete lesson covers basic probability, independent events and mutually exclusive events, reading two-way tables to find conditional probability, and the complement rule for "at least one" problems. Each idea is followed by a fully worked example, and then a set of original practice problems with instant feedback. Everything here is free, and you can keep practicing afterward with the full SAT Math Question Bank linked below.
The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes:
P(event) = number of favorable outcomestotal number of outcomes
Probability is always between 0 (impossible) and 1 (certain), and can be written as a fraction, decimal, or percent.
Worked Example: A bag contains 5 red, 3 blue, and 2 green marbles. What is the probability of randomly selecting a blue marble?
There are 3 + 5 + 2 = 10 total marbles.
P(blue) = 310
1. A standard six-sided die is rolled once. What is the probability of rolling a number greater than 4?
Explanation: The numbers greater than 4 are 5 and 6, two outcomes out of six: 26 = 13.
2. A jar contains 8 red, 5 blue, and 7 yellow candies. What is the probability of randomly selecting a yellow candy?
Explanation: There are 8 + 5 + 7 = 20 candies total. P(yellow) = 720.
3. A standard deck of 52 cards is shuffled. What is the probability of drawing a heart?
Explanation: There are 13 hearts out of 52 cards: 1352 = 14.
4. A spinner is divided into 8 equal sections numbered 1 through 8. What is the probability of landing on an even number?
Explanation: The even numbers from 1 to 8 are 2, 4, 6, 8, four out of eight: 48 = 12.
Two events are independent if the outcome of one doesn't affect the probability of the other. For independent events, multiply their individual probabilities to find the probability of both happening:
P(A and B) = P(A) × P(B)
Two events are mutually exclusive if they cannot both happen at the same time. For mutually exclusive events, add their individual probabilities to find the probability of either happening:
P(A or B) = P(A) + P(B)
Worked Example: A coin is flipped and a die is rolled. What is the probability of getting heads AND rolling a 6?
These events are independent, one doesn't affect the other.
P(heads and 6) = 12 × 16 = 112
1. A fair coin is flipped twice. What is the probability of getting heads both times?
Explanation: The two flips are independent: 12 × 12 = 14.
2. A bag contains 4 red and 6 blue marbles. A marble is drawn, replaced, and a second marble is drawn. What is the probability both marbles are red?
Explanation: Since the marble is replaced, each draw has P(red) = 410 = 25, and the draws are independent: 25 × 25 = 425.
3. Two dice are rolled. What is the probability that the first die shows a 3 AND the second die shows an even number?
Explanation: The two dice are independent: P(3) = 16 and P(even) = 36 = 12. 16 × 12 = 112.
4. A single card is drawn from a standard deck. What is the probability that the card is a king OR a queen?
Explanation: A card can't be both a king and a queen, so these events are mutually exclusive: 452 + 452 = 852 = 213.
5. A single six-sided die is rolled. What is the probability of rolling a 2 OR a 5?
Explanation: Rolling a 2 and rolling a 5 are mutually exclusive: 16 + 16 = 26 = 13.
A two-way table organizes data by two categories at once and is a common way the SAT presents information for conditional probability questions. A conditional probability, "the probability of A given B," restricts your attention to only the row or column matching the given condition, then asks what fraction of that restricted group also satisfies the first condition.
| Owns a Car | Doesn't Own a Car | Total | |
|---|---|---|---|
| Male | 120 | 30 | 150 |
| Female | 90 | 60 | 150 |
| Total | 210 | 90 | 300 |
Worked Example: Using the table above, what is the probability that a randomly selected person owns a car, given that they are male?
"Given that they are male" restricts attention to the male row only, 150 people, of whom 120 own a car.
P(car | male) = 120150 = 45
1. Using the table above, what is the probability that a randomly selected person is female, given that they own a car?
Explanation: "Given that they own a car" restricts attention to the car-owner column, 210 people, of whom 90 are female: 90210 = 37.
2. Using the table above, what is the probability that a randomly selected person does not own a car, given that they are female?
Explanation: "Given that they are female" restricts attention to the female row, 150 people, of whom 60 don't own a car: 60150 = 25.
3. Using the table above, what is the overall probability that a randomly selected person owns a car (regardless of gender)?
Explanation: Overall, 210 out of 300 people own a car: 210300 = 710.
4. Using the table above, what is the probability that a randomly selected person is male?
Explanation: There are 150 males out of 300 total people: 150300 = 12.
5. Using the table above, what is the probability that a randomly selected person is male AND owns a car?
Explanation: Unlike the conditional probability questions above, this asks for the joint count out of the grand total: 120300 = 25.
The complement of an event is everything that event does not include. Since an event and its complement together account for every possible outcome:
P(not A) = 1 − P(A)
This rule is especially useful for "at least one" problems, which are often much easier to solve by finding the probability of the opposite, "none," and subtracting from 1.
Worked Example: A fair coin is flipped 3 times. What is the probability of getting at least one heads?
It's easier to find the complement, getting zero heads (all tails), first.
P(all tails) = 12 × 12 × 12 = 18
P(at least one heads) = 1 − 18 = 78
1. The probability of an event occurring is 38. What is the probability that the event does NOT occur?
Explanation: P(not A) = 1 − 38 = 58.
2. A basketball player makes 70% of her free throws. What is the probability she misses a given free throw?
Explanation: 100% − 70% = 30%.
3. A fair coin is flipped 3 times. What is the probability of getting AT LEAST one heads?
Explanation: This is the worked example above: P(at least one heads) = 1 − P(all tails) = 1 − 18 = 78.
4. A box contains 10 lightbulbs, 2 of which are defective. If one bulb is selected at random, what is the probability it is NOT defective?
Explanation: P(defective) = 210 = 15. P(not defective) = 1 − 15 = 45.
Ask whether the outcome of one event changes the possible outcomes or probabilities of the other. Flipping a coin twice, or rolling two separate dice, are independent, since one result doesn't affect the other. Drawing cards from a deck without replacement is not independent, since removing a card changes what remains.
Find the row or column that matches the "given" condition, treat that row or column's total as your new denominator, and use the specific cell that also matches the event you're asked about as your numerator.
"At least one" success is the opposite of "zero" successes, and there's exactly one way to get zero successes (every single trial fails), which is usually much simpler to calculate than adding up every way to get one success, two successes, three successes, and so on.
The Probability & Conditional Probability quiz in the SAT Math Question Bank includes additional original problems on this topic, along with quizzes covering every other Algebra, Advanced Math, Problem-Solving and Data Analysis, and Geometry and Trigonometry skill on the Digital SAT.