7:[["$","script",null,{"type":"application/ld+json","dangerouslySetInnerHTML":{"__html":"{\"@context\":\"https://schema.org\",\"@type\":\"Quiz\",\"name\":\"Quiz 3\",\"description\":\"Probability, conditional probability, and interpreting data tables.\",\"url\":\"https://theschoolofmathematics.com/quiz/psat-8-9-probability-conditional-probability-quiz-3\",\"educationalLevel\":\"Advanced\",\"numberOfQuestions\":10,\"isAccessibleForFree\":true,\"about\":{\"@type\":\"Thing\",\"name\":\"Problem-Solving and Data Analysis - Probability and Conditional Probability\"}}"}}],["$","script",null,{"type":"application/ld+json","dangerouslySetInnerHTML":{"__html":"{\"@context\":\"https://schema.org\",\"@type\":\"BreadcrumbList\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https://theschoolofmathematics.com\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Quizzes\",\"item\":\"https://theschoolofmathematics.com/quiz\"},{\"@type\":\"ListItem\",\"position\":3,\"name\":\"Quiz 3\",\"item\":\"https://theschoolofmathematics.com/quiz/psat-8-9-probability-conditional-probability-quiz-3\"}]}"}}],["$","div",null,{"className":"bg-gradient-to-b from-white via-gray-50 to-white","children":["$","div",null,{"className":"container mx-auto px-4 py-8 md:py-12","children":[["$","div",null,{"className":"mb-12","children":["$undefined",["$","div",null,{"className":"mb-8","children":["$","h1",null,{"className":"text-4xl md:text-5xl lg:text-6xl font-bold text-gray-900 mb-4","children":"Quiz 3"}]}],["$","div",null,{"className":"bg-white rounded-2xl shadow-lg p-6 md:p-8 border border-gray-200","children":[["$","div",null,{"className":"text-lg md:text-xl text-gray-700 mb-8 leading-relaxed prose prose-lg max-w-none","dangerouslySetInnerHTML":{"__html":"

Probability, conditional probability, and interpreting data tables.

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Practice quiz on probability and conditional probability for PSAT 8-9.

"},"excerpt":{"rendered":"

Probability, conditional probability, and interpreting data tables.

"},"featured_media":0,"featured_media_url":"$undefined","acf":{"duree_estimee":"$undefined","niveau_difficulte":"Advanced","categorie":"Problem-Solving and Data Analysis - Probability and Conditional Probability","nombre_questions":10,"score_minimum":70,"ordre_questions":"Fixe","questions":[{"id":"cmrk8f0hx0y7vjg8wteuopkht","texte_question":"$18","type_question":"TexteLibre","explication":"

Use the probability formula.

The number of ceramic tiles is $$25$$.

The total number of tiles is $$120$$.

So, the probability is: $$\\frac{25}{120}$$

Simplify:

$$\\frac{25}{120}=\\frac{5}{24}$$

Final answer: $$\\frac{5}{24}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

5/24

","correcte":true,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0i00y7yjg8w99yffgw5","texte_question":"

Each vertex of a $$12$$-sided polygon is labeled with one of the $$12$$ letters A through L, with a different letter at each vertex. If one vertex is selected at random, what is the probability that the letter F will be at the selected vertex? Express your answer as (a/b)

","type_question":"TexteLibre","explication":"

There are $$12$$ vertices total.

Only $$1$$ vertex is labeled F.

So, the probability of selecting the vertex labeled F is: $$\\frac{1}{12}$$

Final answer: $$\\frac{1}{12}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

1/12

","correcte":true,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0i20y81jg8wg9f94vcx","texte_question":"

At a workshop, there are $$300$$ participants. Each participant is assigned to group X, group Y, or group Z. The probability of selecting a participant from group X is $$0.5$$ and from group Y is $$0.3$$. How many participants are assigned to group Z?

","type_question":"TexteLibre","explication":"

The probabilities for all groups must add to $$1$$.

The probability for group Z is:

$$1-0.5-0.3=0.2$$

There are $$300$$ participants total.

So, the number assigned to group Z is:

$$0.2\\cdot300=60$$

Final answer: $$60$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

","correcte":true,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0i40y84jg8wl1ncmst5","texte_question":"

The table above shows information about $$18$$ cars listed for sale. If one of the cars listed for sale is selected at random, what is the probability that the car selected will be an electric car priced at no more than $$30{,}000$$ dollars?

","type_question":"QCM","explication":"

Use the probability formula.

The total number of cars is $$18$$.

From the table, the number of electric cars priced at no more than $$\\$30{,}000$$ is $$6$$.

So, the probability is: $$\\frac{6}{18}$$

Simplify:

$$\\frac{6}{18}=\\frac{1}{3}$$

Final answer: $$\\frac{1}{3}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"$$$\\frac{2}{9}$$","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{1}{3}$$

","correcte":true,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{4}{9}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{5}{9}$$

","correcte":false,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0i70y8ajg8wogyciatz","texte_question":"$19","type_question":"QCM","explication":"

Find the total number of parks.

$$18+6+10+6=40$$

The number of parks that have hiking trails but no lake is $$6$$.

So, the probability is: $$\\frac{6}{40}$$

Final answer: $$\\frac{6}{40}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"$$$\\frac{6}{40}$$","correcte":true,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{6}{18}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{10}{40}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{18}{40}$$

","correcte":false,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0ia0y8gjg8wyt6n21rb","texte_question":"

The same $$15$$ contestants competed on $$3$$ days. Each day, they could score $$0$$ to $$5$$ points. No contestant received the same score twice. If a contestant is selected at random, what is the probability that the contestant scored $$5$$ on Day $$1$$ or Day $$2$$, given that the contestant scored a $$5$$ on one of the three days? Express your answer as (a/b)

","type_question":"TexteLibre","explication":"

The condition says the contestant scored $$5$$ on one of the three days.

Since no contestant received the same score twice, the contestant could have scored $$5$$ on exactly one of the three days.

The favorable days are Day $$1$$ and Day $$2$$.

There are $$2$$ favorable days out of $$3$$ possible days.

So, the probability is: $$\\frac{2}{3}$$

Final answer: $$\\frac{2}{3}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

2/3

","correcte":true,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0ic0y8jjg8w694skk0l","texte_question":"

A table shows blood type distribution. Among Rh-negative individuals, there are $$12$$ with type A, $$6$$ with type B, $$2$$ with type AB, and $$x$$ with type O. If the probability that a randomly selected Rh-negative individual has type B is $$\\frac{1}{5}$$, what is the value of $$x$$?

","type_question":"TexteLibre","explication":"

The number of Rh-negative individuals with type B is $$6$$.

The total number of Rh-negative individuals is:

$$12+6+2+x=20+x$$

The probability of selecting a type B individual is: $$\\frac{6}{20+x}$$

Set this equal to $$\\frac{1}{5}$$.

$$\\frac{6}{20+x}=\\frac{1}{5}$$

Cross multiply:

$$30=20+x$$

Subtract $$20$$ from both sides: $$x=10$$

Final answer: $$10$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

","correcte":true,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0ie0y8mjg8wuxphgnf2","texte_question":"$1a","type_question":"QCM","explication":"

This is a conditional probability.

The condition is that the day had no rain.

There are $$54$$ days with no rain.

Among those, $$14$$ were weekend days.

So, the probability is: $$\\frac{14}{54}$$

Final answer: $$\\frac{14}{54}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

$$\\frac{14}{54}$$

","correcte":true,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{54}{70}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{14}{20}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{20}{54}$$

","correcte":false,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0ih0y8sjg8wetqt704g","texte_question":"$1b","type_question":"TexteLibre","explication":"

The condition is that the participant is at least $$18$$ years old.

The total number of participants at least $$18$$ years old is:

$$50+30=80$$

The number of Team $$1$$ participants at least $$18$$ years old is:

$$20+10=30$$

So, the conditional probability is: $$\\frac{30}{80}$$

Simplify:

$$\\frac{30}{80}=\\frac{3}{8}$$

Final answer: $$\\frac{3}{8}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

3/8

","correcte":true,"explication":"","imageUrl":"$undefined"}]},{"id":"cmrk8f0ik0y8vjg8wtswef15a","texte_question":"$1c","type_question":"QCM","explication":"

The condition is that the person is from the Sales department.

In Sales, there are:

$$6+3=9$$

There are $$3$$ people in Sales with a master's degree.

So, the probability is: $$\\frac{3}{9}$$

Final answer: $$\\frac{3}{9}$$

","points":1,"temps_limite":60,"reponses":[{"texte":"

$$\\frac{3}{9}$$

","correcte":true,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{3}{10}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{6}{9}$$

","correcte":false,"explication":"","imageUrl":"$undefined"},{"texte":"

$$\\frac{7}{10}$$

","correcte":false,"explication":"","imageUrl":"$undefined"}]}]},"categories":["problem-solving-and-data-analysis-probability-and-conditional-probability"],"date":"2026-06-04T09:04:49.161Z","modified":"2026-07-14T05:49:54.113Z"}}],["$","div",null,{"className":"container mx-auto px-4 pb-12","children":["$","$L1d",null,{"targetType":"quiz","targetSlug":"psat-8-9-probability-conditional-probability-quiz-3"}]}]]}]}]]

Quiz 3

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