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ACT Math, ACT Prep, Percentages

ACT Math Percentages Complete Study Guide

ACT Math: Percentages – Complete Study Guide | The School of Mathematics
ACT Math — Full Lesson

Percentages & Percent Reasoning

A complete, test-focused breakdown of every Percentages concept on the ACT — from the three core question types to percent change, successive percents, reverse percent problems, compound interest, and real-world percent word problems — with worked examples and strategy notes for every question type you'll encounter.

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Percent Foundations & Conversions

Percent means "per hundred" — it is simply a ratio with a denominator of 100. Every percentage problem ultimately involves converting between percent, decimal, and fraction form.

Percent ↔ Decimal: Divide by 100 (move decimal 2 places LEFT)
Decimal ↔ Percent: Multiply by 100 (move decimal 2 places RIGHT)
Percent ↔ Fraction: P% = P/100 (then simplify)
// 45% = 0.45 = 45/100 = 9/20

Must-Know Conversions

1%
0.01
1/100
5%
0.05
1/20
10%
0.10
1/10
12.5%
0.125
1/8
20%
0.20
1/5
25%
0.25
1/4
33.3%
0.333…
1/3
37.5%
0.375
3/8
50%
0.50
1/2
62.5%
0.625
5/8
66.7%
0.667…
2/3
75%
0.75
3/4
80%
0.80
4/5
87.5%
0.875
7/8
100%
1.00
1/1
125%
1.25
5/4
💡

Mental math shortcut — 10% trick: To find 10% of any number, move the decimal one place left. Then use it to build other percentages: 5% = half of 10%; 20% = double 10%; 15% = 10% + 5%; 30% = 3 × 10%. This is faster than multiplying on most ACT problems.

📐 Worked Example — Conversion
Convert each: (a) 0.375 to a percent, (b) 140% to a decimal, (c) 7/8 to a percent
a0.375 × 100 = 37.5%
b140 ÷ 100 = 1.40
c7 ÷ 8 = 0.875 × 100 = 87.5%
37.5% · 1.40 · 87.5%

The Three Core Percent Questions

Every basic percent problem on the ACT is one of three types. Identify the type, plug into the formula, solve. All three come from the same master equation: Part = Percent × Whole.

Part = (Percent / 100) × Whole
// Rearrange to solve for any of the three unknowns
Type A
What is P% of W?
Part = (P/100) × W

What is 35% of 80?
= 0.35 × 80 = 28
Type B
X is what % of W?
% = (X / W) × 100

18 is what % of 72?
= (18/72) × 100 = 25%
Type C
X is P% of what?
W = X / (P/100)

24 is 60% of what?
= 24 / 0.60 = 40
📐 Worked Example — Type A
What is 72% of 350?
01Convert 72% to decimal: 0.72
02Multiply: 0.72 × 350 = 252
252
📐 Worked Example — Type B
45 is what percent of 180?
01Part = 45, Whole = 180
02% = (45/180) × 100 = 0.25 × 100 = 25%
25%
📐 Worked Example — Type C
84 is 35% of what number?
01Part = 84, Percent = 35% = 0.35, Whole = ?
02Whole = Part ÷ Percent = 84 ÷ 0.35 = 240
240
💡

Universal setup — "IS over OF": Any percent problem can be set up as:
(IS / OF) = (Percent / 100)
"IS" is the part you're looking at. "OF" is the whole. Cross-multiply to solve for whichever is unknown.

Percent Change (Increase & Decrease)

Percent change measures how much a quantity has changed relative to its original value. The original value is always the denominator — this is where most errors occur.

% Change = [(New Value − Original Value) / Original Value] × 100
// Positive result → increase. Negative result → decrease.
// Always divide by the ORIGINAL (starting) value — never the new value.
📐 Worked Example — Percent Increase
A stock price rises from $40 to $54. What is the percent increase?
01Change = 54 − 40 = 14
02% Increase = (14 / 40) × 100 = 35%
35% increase
📐 Worked Example — Percent Decrease
A jacket's price drops from $120 to $84. What is the percent decrease?
01Change = 84 − 120 = −36
02% Change = (−36 / 120) × 100 = −30%
30% decrease
📐 Worked Example — Finding the New Value from % Change
A salary of $65,000 increases by 8%. What is the new salary?
01Increase amount = 8% × $65,000 = 0.08 × 65,000 = $5,200
02New salary = $65,000 + $5,200 = $70,200
New salary = $70,200
⚠️

Original vs. New — the most common ACT trap: "A price increased from $50 to $60, what percent of the NEW price is the increase?" → 10/60 = 16.7%. "What percent INCREASE?" → 10/50 = 20%. The denominator changes the answer completely. Always identify what the base is before dividing.

The Multiplier Method

The multiplier method is the fastest way to apply a percent increase or decrease — instead of calculating the change and adding it, you multiply by a single number. This is especially powerful for multi-step percent problems.

The Core Idea

Increase by P%: multiply by (1 + P/100)
Decrease by P%: multiply by (1 − P/100)

The multiplier captures the original 100% plus or minus the change — in one step.

Common Multipliers to Memorize

×0.75
25% off
·
×0.80
20% off
·
×0.90
10% off
·
×1.00
no change
·
×1.10
10% up
·
×1.20
20% up
·
×1.50
50% up
📐 Worked Example — Multiplier in One Step
A price of $240 is discounted by 15%. Find the sale price.
01Multiplier for 15% decrease: 1 − 0.15 = 0.85
02Sale price = $240 × 0.85 = $204
Sale price = $204
📐 Worked Example — Finding the Original from the Multiplier
After a 20% increase, a number equals 96. What was the original number?
01Multiplier for 20% increase: 1.20
02Original × 1.20 = 96
03Original = 96 ÷ 1.20 = 80
Original = 80

The multiplier method is faster than the two-step approach on the ACT. Instead of finding 15% of $240 ($36) and then subtracting ($240 − $36 = $204), you multiply once: $240 × 0.85 = $204. Save 10 seconds per problem — that adds up across the test.

Successive Percent Changes

When a value undergoes multiple percent changes in sequence, the changes compound — each one applies to the result of the previous change, not the original value. This makes successive percents one of the most heavily tested and most misunderstood ACT topics.

The Golden Rule

Chain-multiply the multipliers:

Final Value = Original × (Multiplier₁) × (Multiplier₂) × (Multiplier₃) × …

Never add or subtract the percentages directly. A 30% increase followed by a 30% decrease does NOT return to the original — you lose money.

📐 Worked Example — Increase Then Decrease
A price increases by 20%, then decreases by 20%. What is the net percent change?
01Multiplier 1 (20% increase): 1.20
02Multiplier 2 (20% decrease): 0.80
03Combined: 1.20 × 0.80 = 0.96
040.96 means the final value is 96% of the original → net change = −4%
Net result: 4% decrease (not 0%)
📐 Worked Example — Three Successive Changes
A $500 investment increases by 10%, then by 20%, then decreases by 15%. Find the final value.
01Multipliers: 1.10 × 1.20 × 0.85
021.10 × 1.20 = 1.32
031.32 × 0.85 = 1.122
04Final value: $500 × 1.122 = $561
Final value = $561 (net increase of 12.2%)
📐 Worked Example — The Classic "Same %" Trap
A TV's price increases by 25%, then is discounted by 25%. What fraction of the original price is the final price?
01Combined multiplier: 1.25 × 0.75 = 0.9375
02Final price = 93.75% of original → a 6.25% net decrease
03As a fraction: 0.9375 = 15/16 of the original price
Final price is 15/16 of the original (not equal to it)
⚠️

Why P% up then P% down always loses money: The increase applies to a smaller base, but the decrease applies to a larger base. After a 25% increase on $100, you have $125. A 25% decrease on $125 removes $31.25 — bringing you to $93.75, not back to $100. The loss is always (P/100)² of the original.

Reverse Percent Problems

A reverse percent problem gives you the value after a percent change and asks for the value before. This is Type C thinking applied to percent change — and the most common ACT percent trap.

The Trap to Avoid

If a price is $80 after a 20% discount, the original is NOT $80 + 20% of $80 = $96.

The 20% was taken off the original, not the sale price. You must divide by the multiplier:

Original = Final Value ÷ Multiplier

📐 Worked Example — Finding the Original Price
After a 20% discount, a shirt costs $56. What was the original price?
01The sale price represents (100% − 20%) = 80% of the original
02Multiplier = 0.80. So: Original × 0.80 = $56
03Original = $56 ÷ 0.80 = $70
04Check: $70 × 0.80 = $56 ✓
Original price = $70
📐 Worked Example — After a Percent Increase
A population grew by 15% and is now 23,000. What was the population before the increase?
01Multiplier for 15% increase: 1.15
02Original × 1.15 = 23,000
03Original = 23,000 ÷ 1.15 = 20,000
Original population = 20,000
📐 Worked Example — Two-Step Reverse
A value decreased by 10% then increased by 30%, resulting in 117. Find the original value.
01Forward: Original × 0.90 × 1.30 = 117
02Combined multiplier: 0.90 × 1.30 = 1.17
03Original = 117 ÷ 1.17 = 100
Original value = 100
⚠️

The wrong approach everyone tries: "Price is $56 after 20% off, so add back 20% of $56 = $11.20, giving $67.20." This is wrong because 20% of $56 ≠ 20% of the original. Always divide by the multiplier — never add a percent of the sale price back.

Percent of a Total & Part/Whole Reasoning

Many ACT percent problems involve identifying what is the "part" and what is the "whole" in a real-world context. Getting this wrong is the single biggest source of errors on percentage problems.

Identifying Part and Whole

The WHOLE is always what follows "of" "What percent of the students passed?" → students = whole

"30% of the budget was spent" → budget = whole
The PART is the subset you're examining "15 students passed" → 15 = part

"The amount spent" → amount = part
📐 Worked Example — Multi-Layer Part/Whole
In a school of 800 students, 60% are female. Of the female students, 45% play sports. How many female students play sports?
01Female students: 60% × 800 = 480
02Female athletes: 45% × 480 = 216
216 female students play sports
📐 Worked Example — Percent of the Whole from Nested Percents
Using the same school above, what percent of ALL students are female athletes?
01Female athletes = 216 (from above)
02Total students = 800
03% = (216 / 800) × 100 = 27%
04Or directly: 60% × 45% = 0.60 × 0.45 = 0.27 = 27%
27% of all students are female athletes
💡

Nested percent shortcut: When you need "X% of Y% of the whole," you can multiply the percents directly: 60% × 45% = 27% of the whole. This works because percentage multiplication is associative — no need to find the intermediate group size.

Tax, Tip, Discount & Markup

These are the most common real-world applications of percentages on the ACT. Each follows the same multiplier logic — know the formula for each and you'll never be stuck.

SituationFormulaMultiplierExample
Tax Final = Original × (1 + tax rate) 1 + r $50 + 8% tax = $50 × 1.08 = $54
Tip Total = Bill × (1 + tip rate) 1 + r $80 bill + 20% tip = $80 × 1.20 = $96
Discount Sale = Original × (1 − discount rate) 1 − r $120 − 30% off = $120 × 0.70 = $84
Markup Selling Price = Cost × (1 + markup rate) 1 + r Cost $60, markup 40% → $60 × 1.40 = $84
📐 Worked Example — Stacked Discount then Tax
A laptop costs $800. It is discounted 25%, then 8% sales tax is applied to the sale price. What is the final price?
01After 25% discount: $800 × 0.75 = $600
02After 8% tax: $600 × 1.08 = $648
Final price = $648
📐 Worked Example — Markup and Gross Profit
A store buys shoes for $45 and sells them at a 60% markup. A customer uses a coupon for 15% off the selling price. What does the customer pay, and what is the store's profit?
01Selling price after markup: $45 × 1.60 = $72
02Customer price after 15% off: $72 × 0.85 = $61.20
03Store's profit: $61.20 − $45.00 = $16.20
Customer pays $61.20 · Store profits $16.20
⚠️

Order matters for stacked operations! A 25% discount followed by 8% tax gives a different answer than 8% tax followed by a 25% discount on the taxed amount. On the ACT, always apply operations in the order stated in the problem.

Simple & Compound Interest

Simple Interest

Simple interest is calculated on the original principal only — interest earned in earlier periods does not earn additional interest.

Simple Interest (I) = P × r × t
Total Amount (A) = P + I = P(1 + rt)
// P = principal, r = annual interest rate (decimal), t = time (years)
📐 Worked Example — Simple Interest
$3,000 is invested at 5% simple annual interest for 4 years. Find the total interest and the total amount.
01I = P × r × t = 3,000 × 0.05 × 4 = $600
02Total amount = $3,000 + $600 = $3,600
Interest = $600 · Total = $3,600

Compound Interest

Compound interest earns interest on both the principal and previously earned interest. It grows faster than simple interest because each period's interest becomes part of the next period's base.

A = P × (1 + r/n)^(nt)
// P = principal, r = annual rate (decimal), n = compounding periods per year, t = years
// Annual: n=1 · Semi-annual: n=2 · Quarterly: n=4 · Monthly: n=12 · Daily: n=365
📐 Worked Example — Compound Interest
$2,000 is invested at 6% annual interest compounded quarterly for 3 years. Find the total amount.
01P = 2,000 ; r = 0.06 ; n = 4 (quarterly) ; t = 3
02A = 2,000 × (1 + 0.06/4)^(4×3)
03= 2,000 × (1.015)^12
04= 2,000 × 1.19562 ≈ $2,391.24
Total amount ≈ $2,391.24

Compound Interest — Year by Year (Simple Version)

For small numbers of years and annual compounding, the ACT may expect you to build a year-by-year table. Each year's amount = previous year × (1 + r).

Year 0Principal$1,000
Year 1$1,000 × 1.10$1,100
Year 2$1,100 × 1.10$1,210
Year 3$1,210 × 1.10$1,331

$1,000 at 10% annual compound interest for 3 years = $1,331. Simple interest would give only $1,300.

Simple vs. Compound — The Difference

Simple interest: $1,000 × 10% × 3 years = $300 interest → $1,300 total.
Compound interest: $1,000 × (1.10)³ = $1,331 total → $331 interest.

Compound interest earns $31 more because interest earned in years 1 and 2 also earns interest in later years.

Percent Word Problems

Strategy: Label Everything Before Calculating

On percent word problems, identify three things before touching the calculator: (1) What is the whole? (2) What is the part? (3) What is the percent? Then plug into Part = Percent × Whole.

📐 Worked Example — Election Problem
In an election, Candidate A received 54% of the 25,000 votes cast. Candidate B received the rest. How many more votes did A receive than B?
01Candidate A's votes: 54% × 25,000 = 13,500
02Candidate B's votes: 25,000 − 13,500 = 11,500
03Difference: 13,500 − 11,500 = 2,000
Candidate A received 2,000 more votes
📐 Worked Example — Mixture / Concentration Problem
A 200 mL solution is 30% acid. How many mL of pure acid must be added to make a 50% acid solution?
01Acid in original: 30% × 200 = 60 mL
02Let x = mL of acid added. New solution: (200 + x) mL total, (60 + x) mL acid
03Set up equation: (60 + x)/(200 + x) = 0.50
0460 + x = 0.50(200 + x) = 100 + 0.5x
050.5x = 40 → x = 80 mL
Add 80 mL of pure acid
📐 Worked Example — Salary After Multiple Raises
An employee earns $50,000. She receives a 10% raise in Year 1 and an 8% raise in Year 2 on top of the Year 1 salary. What is her salary after both raises?
01Year 1 salary: $50,000 × 1.10 = $55,000
02Year 2 salary: $55,000 × 1.08 = $59,400
03Or in one step: $50,000 × 1.10 × 1.08 = $59,400
Salary after both raises = $59,400
📐 Worked Example — Survey / Sample Problem
A survey of 400 students found that 65% prefer pizza. The school has 1,200 students. Based on the survey, how many students in the entire school prefer pizza?
01Survey result: 65% prefer pizza
02Apply to full school: 65% × 1,200 = 0.65 × 1,200 = 780
Approximately 780 students prefer pizza

Test Day Strategy

Top ACT Percent Traps

  • Wrong base for percent change: always divide by the ORIGINAL, never the new value.
  • Successive percents: 20% up + 20% down ≠ 0% — always chain-multiply multipliers.
  • Reverse percent: don't add a% of the sale price to find the original — divide by the multiplier.
  • Average of percents: if group sizes differ, you can't average percent rates directly.
  • Percent vs. percentage points: "rose from 20% to 25%" is a 5 percentage point increase, but a 25% relative increase.
  • Compound vs. simple interest: only compound interest earns interest on interest — know the difference.

Decision Framework

  • Find P% of W → multiply: W × (P/100)
  • X is what % of W? → divide: (X/W) × 100
  • X is P% of what? → divide: X ÷ (P/100)
  • Apply percent change → use multiplier method: × (1 ± r)
  • Multiple changes → chain-multiply all multipliers
  • Find original from final → divide final by multiplier
  • Interest problem → identify simple (I=Prt) vs. compound (A=P(1+r/n)^nt)

Complete Formula Reference

ConceptFormulaWatch-out
Part of a wholePart = (P/100) × WholeIdentify what the "whole" is first
Percent of a total% = (Part / Whole) × 100The "OF" value is the denominator
Reverse: find wholeWhole = Part ÷ (P/100)Divide by the percent, don't subtract
Percent change% = [(New − Old)/Old] × 100Old (original) in denominator
New value after increaseNew = Old × (1 + r)r is decimal form of rate
New value after decreaseNew = Old × (1 − r)r is decimal form of rate
Successive changesFinal = Original × m₁ × m₂ × …Never add/subtract the percents
Reverse percentOriginal = Final ÷ MultiplierDon't apply % to the wrong value
Nested percentsP% of Q% of W = (P×Q)/10000 × WMultiply decimal forms directly
Simple interestI = Prt ; A = P(1 + rt)Interest on principal only
Compound interestA = P(1 + r/n)^(nt)n = compounds per year
~6–10 questions per test High ROI — few formulas, many applications Appears on every ACT

Put It to the Test

You've mastered every percentage concept the ACT tests. Now build speed and accuracy with 5 quizzes of ACT-style timed questions. Work through each quiz in order — difficulty increases progressively.

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